Школьная математика. Первое домашнее задание

Первое домашнее задание курса школьной математики

  1. \displaystyle\frac{2^4\cdot (12)^4}{9^2\cdot (18)^3}
  2. \displaystyle\frac{a^4(b^3c)^{-2}}{(ab^4)^{-3}(c^{-3})^2}
  3. \displaystyle\frac{2}{3}+\displaystyle\frac{5}{6}:\displaystyle\frac{15}{12}-\displaystyle\frac{13}{9}
  4. (x-1)(x-3)-(x+2)(3-x)
  5. (x-10)(x+10)-(2x+3)(2x-3)
  6. 6b^2-(2b+5)(3b-7)
  7. -1-(2x-(x+1)(2x+1))-2x^2
  8. (x-2)(3x+4)-x(3x-2)
  9. (2x^2-4)(3x^2+2)-(x^2-1)(6x^2+6)
  10.  49x^3-x(7x+5)(7x-5)
  11. (a+b)(a-b+1)-(a-b)(a+b-1)
  12. (x+2-x^2)(2-x)+3(1-\frac{x^3}{3})
  13. (1+x)(2+x)(3+x)-(x+2)(x+1)
  14. 1-(x^2-x)(x^2+x)+x^3(x+1)
  15. (2+x-3x^2+x^3)(2-x+3x^2+x^3)
  16. (x-2)(x^4+2x^3+4x^2+8x+16)
  17. (x+3y)(x+y+2)-(x+y)(x+3y+2)
  18. (3+5-6)\cdot(-2-3+6)
  19. -4\displaystyle\frac{1}{3}-(-\displaystyle\frac{2}{5}+\displaystyle\frac{3}{7})
  20. \displaystyle\frac{1}{2(3-2)}-\displaystyle\frac{2(2-4)}{3-5}
  21. \frac{5}{4}-\frac{4}{13}\cdot\frac{26}{8}+8:\frac{44}{33}
  22. \displaystyle\frac{49^4\cdot 50^3\cdot 3^5:8}{9^3\cdot 35^3\cdot 25:7^{-5}}
  23. (2,5+2\frac{1}{2})\cdot\frac{8}{12}-(\frac{7}{2}+\frac{18}{27})\cdot\frac{8}{24}-6,2
  24. \frac{x}{5}-\frac{1}{3}+\frac{2}{9}=\frac{3x}{27}-\frac{6}{15}
  25. 4(-x+2)-7(2x+3)=5
  26. 2x+\displaystyle\frac{1}{3}(7-4x)=0
  27. -\displaystyle\frac{1}{6}(-2x-3)=\displaystyle\frac{1}{6}(3x+3)
  28. x+5(2-x+3(x-1)-x)=0
  29. -(x-4(x-4))=x-4
  30. 4-2(8-7(2x-3))=x
  31. \displaystyle\frac{x}{3}+\displaystyle\frac{2x-3}{6}=0
  32. -\displaystyle\frac{x}{2}+x-\displaystyle\frac{3}{4}=0
  33. \displaystyle\frac{x+1}{2}=1-\displaystyle\frac{x-1}{3}
  34. (x-4)\cdot\displaystyle\frac{7}{8}=\displaystyle\frac{5x}{4}-\displaystyle\frac{35}{4}
  35. \displaystyle\frac{x-8}{2}=\displaystyle\frac{8-2x}{3}
  36. \displaystyle\frac{2x}{5}-\displaystyle\frac{5x+1}{10}=-0,1
  37. 6-x-\displaystyle\frac{7x-8}{3}=0
  38. \frac{x}{2}+\frac{x}{3}+\frac{x}{4}=2-\frac{x}{8}
  39. \displaystyle\frac{2x}{3}\cdot (2-0,1)+\displaystyle\frac{x}{4}:2,2=1-\displaystyle\frac{x}{2}
  40. \displaystyle\frac{x}{1\cdot 2\cdot 3}+\displaystyle\frac{x}{2\cdot 3\cdot 4}=\displaystyle\frac{2x}{4\cdot 5\cdot 6}-0,2
  41. (\frac{41}{18}-\frac{17}{36})\cdot\frac{18}{65}+(\frac{8}{7}-\frac{23}{49}):\frac{99}{49}+\frac{7}{6}
  42. \frac{10}{16}+\frac{3}{2}\cdot (\frac{17}{4}:17)+3,75:\frac{5}{6}
  43. \frac{217}{31}:1,75-(3,5:\frac{5}{4}+\frac{7}{2})+3,4:\frac{17}{8}
  44. (\frac{14}{15}+\frac{5}{2}+0,3)\cdot \frac{8}{7}\cdot 0,75+\frac{5}{10}
  45. (1+x+y)(1-(x+y))
  46. a^3-(a-4)(a^2+3a+12)-a(a+3)
  47. (x+2)(x^2-2x+4)-(x^2-3x)(x+3)
  48. (3d^3-4)(9d^6+12d^3+16)
  49. \displaystyle\frac{ab^3}{a^2b}
  50. \displaystyle\frac{(a^2)^3b}{a^5(b^3)^2}
  51. \displaystyle\frac{5abc}{25ab^{-1}c^2}
  52. \displaystyle\frac{18}{c^4}\cdot\frac{2c^3}{27}
  53. \displaystyle\frac{7(-a)^3(b^{-1})^2}{21(ab)^2a^{-2}}
  54. \displaystyle\frac{144a^2b}{12b^3a^8}
  55. \displaystyle\frac{3}{2a^2}\cdot\frac{4a}{9}
  56. \displaystyle\frac{2a^8b^9}{4(ab)^3}
  57. \displaystyle\frac{a^{-1}b^2c^4}{(ab)^2(bc)^2(ac)^3}
 

Комментариев 2 к “Школьная математика. Первое домашнее задание

  1. 2) a^7b^6c^4
    4) 2x^2-5x-3
    6) 35-b
    8) -8
    10) 25x
    12) -3x^2+7
    14) x^3+x^2+1
    16) x^5-32
    18) 2
    20) -3/2
    22) 5/3
    24) -25/4
    26) -7/2
    28) 5/6
    30) 2
    32) 3/2
    34) 14
    36) 0
    38) 48/29
    40) -24/21

  2. 41) 2
    42) 11/2
    43) -7/10
    44) 37/10
    45) -x^2-y^2-2xy+1
    46) -3a+48
    47) 9x+8
    48) 27d^9-64
    49) b^2/a
    52) 4/(3c)
    54)12/(a^6b^2)

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