Задачи по школьной математике. Линейные уравнения. Часть 2

Линейные уравнения

$2x=4$
$3x=-9$
$-4x=8$
$3x=7$
$3(x+1)-4(x-2)=9$
$4(x-1)+2(3-x)=7x$
$x+2x+3x=1+2+3$
$x+2(x+3(x+4))=8$
$x+3=x+2$
$2(x+2)=2(x+3)$
$2015+x=x+2015$
$\displaystyle\frac{x}{2}=\frac{1}{6}$
$\displaystyle\frac{x+1}{2}=\frac{x-1}{5}$
$\displaystyle\frac{x}{3}-\frac{x}{4}=\frac{1}{6}$
$\displaystyle\frac{2x-3}{15}+\frac{1-x}{9}=\frac{2-x}{6}-1$
$(x+1)(x+2)=(x-1)(x-100)$
$2015(x-1)+x^2=x(2016+x)+2015$
$2(x-(x-(x-(x-10))))=3(1-(1-(1-x)))$
$\displaystyle\frac{50}{x}=\frac{2}{9}$
$\displaystyle\frac{4}{x-1}=\frac{3}{x+3}$
$0,5+2x=1,5+3x$
$\displaystyle\frac{3}{5}x-\frac{x}{2}=0,2$
$\displaystyle\frac{17}{5x}=2-\frac{7}{x}$
$(x+2)^2-5(x-4)=(x-6)(x+6)$
$\displaystyle\frac{17x+26}{4x+3}-3=0$
$6-\displaystyle\frac{x-1}{2}=\frac{3-x}{2}+\frac{x-2}{3}$
$\displaystyle\frac{2}{3}(x+3)=\frac{6+2x}{3}$
$0,2(x-1)+0,5(3x-9)=\displaystyle\frac{x}{3}-2$
$3(-0,5+2x^2-(x+2)(2x-4))=-20+5x$
$\displaystyle\frac{x}{2}+\frac{x}{12}+\frac{x}{42}=-6-\frac{x}{30}-\frac{x}{20}$
$7-2(x-3(x-3(x-3)))=2$
$(x-3)^2-x(x+4)=15-10x$
$\displaystyle\frac{8}{9}x+\frac{34}{72}-\frac{9}{8}x=0$
$\displaystyle\frac{4+x}{4x-2}+\frac{3}{4}=0$
$\displaystyle\frac{5}{x}+\frac{1}{x^2}=0$
$\displaystyle\frac{3}{2-\frac{3}{2-x}}=\frac{21}{8}$