Квадратные уравнения

Смотрите статью “Как решать квадратные уравнения”
- \(x^2-2x=0\)
- \(2x^2=0\)
- \(x^2-16=0\)
- \(4x^2=8x\)
- \(x^2-5x+6=0\)
- \(2x^2-16x+14=0\)
- \(x^2-2=0\)
- \(7x-2x^2=0\)
- \(x^2-4x+4=0\)
- \(x^2+3x+6=0\)
- \(\displaystyle\frac{7}{x+4}+x=4\)
- \(x+\displaystyle\frac{1}{x}=2,5\)
- \(\displaystyle\frac{x^2-25}{x+1}=0\)
- \(\displaystyle\frac{x}{2x+3}=\frac{1}{x}\)
- \(\displaystyle\frac{1}{x}+\frac{2}{x+2}=1\)
- \(\displaystyle\frac{x^2-x-2}{x^2-3x+2}=0\)
- \(2x^2+x-3=0\)
- \(\displaystyle\frac{x}{x+1}-\frac{x+2}{x-2}=1\)
- \(\displaystyle\frac{4}{x}+5=\frac{1}{x^2}\)
- \(\displaystyle\frac{x^3-8}{x-2}=6x+1\)
- \((x+3)^3-(x+1)^3=56\)
- \(0,01x^2=4\)
- \(3x^2=5\displaystyle\frac{1}{3}\)
- \(4=\displaystyle\frac{x^2-5}{5}\)
- \(15x+9x^2=7x^2+10x\)
- \(x(x-15)=3(108-5x)\)
- \((x-7)(x+3)+(x-1)(x+5)=102\)
- \((2x+1)(x-3)-(1-x)(x-5)=29-11x\)
- \((3x-8)^2-(4x-6)^2+(5x-2)(5x+2)=96\)
- \(\displaystyle\frac{x^2-9}{x-3}=0\)
- \(3x(x-2)-x+1=-0,5(x^2+8)+2\)
- \(2,5x^2-30,75x+93,8=0\)
- \(\displaystyle\frac{2x^2+x}{3}-\frac{2-3x}{4}=\frac{x^2-6}{6}\)
- \(\displaystyle\frac{10}{x-3}-\frac{8}{x}=1\)
- \(\displaystyle\frac{2}{x-5}+\frac{14}{x}=3\)
- \(\displaystyle\frac{1}{x}+\frac{1}{x+3}=\frac{3}{20}\)
- \(\displaystyle\frac{40}{x-20}-\frac{40}{x}=1\)
- \(\displaystyle\frac{x^2}{x+3}-\frac{x}{-x-3}=\frac{6}{x+3}\)
- \(\displaystyle\frac{x^2}{x-1}-\frac{2x}{1-x}=\frac{3}{x-1}\)
- \(\displaystyle\frac{(x+2)^2}{3}-\frac{(x+1)^2}{2}=1\)
- \(\displaystyle\frac{(x-1)^2}{4}-\frac{(x-2)^2}{5}=4\)
- \((x-2)(x+8)=6x\)
- \(\displaystyle\frac{x}{x-2}+\frac{3}{x}=\frac{3}{x-2}\)
- \(\displaystyle\frac{y+3}{y^2-y}+\frac{6-y}{1-y^2}=\frac{y+5}{y+y^2}\)
- \(\displaystyle\frac{y+4}{y-4}-\frac{y}{4-y}=2-\frac{4}{y}\)
- \(\displaystyle\frac{5x^2+9}{6}-\frac{4x^2-9}{5}=3\)
- \(\displaystyle\frac{x(x-3)}{7}-11=-x\)
- \((x-3)^2+(x+4)^2-(x-5)^2=17x+24\)
- \(\displaystyle\frac{5}{4}x^2-x+\frac{1}{9}=0\)
- \(\displaystyle\frac{x^2}{5}-\frac{2x}{3}=\frac{x+5}{6}\)
- \(\displaystyle\frac{3x^2-11}{8}+\frac{74-2x^2}{12}=10\)
- \(2(x-2)(x+2)=(x+1,5)^2+4(x-5\frac{1}{16})\)
- \(3+\displaystyle\frac{5}{x-1}=\frac{2}{x+2}\)
- \(5+\displaystyle\frac{2}{x-2}=\frac{17}{x+3}\)
- \(1+\displaystyle\frac{5x}{x+1}=\frac{6x+2}{(x+1)^2}\)
1) 0; 2
2) 0
3) +-4
4) 0; 2
5) 2; 3
6) 1; 7
7) +-корень(2)
8) 0; 7/2
9) 2
10) нет корней
11) +-3
12) 2; 1/2
13) +-5
14) -1; 3
15) -1; 2
16) -1
17) 1; -3/2
18) 0; -4
19) -1; 1/5
20) 1; 3
21) (-6+-корень(165))/3
22) +-20
23) +-4/3
24) +-5
25) 0; -5/2
26) +-18
27) нет корней
30) -3
44) 2;4
48) -3;8
55) -1/2;1/3