Задачи по школьной математике. Дробно-рациональные неравенства III

  1. \(\displaystyle\frac{0,5}{x-x^2-1}<0\)
  2. \(\displaystyle\frac{x^2-5x+6}{x^2+x+1}<0\)
  3. \(\displaystyle\frac{x^2+2x-3}{x^2+1}<0\)
  4. \(\displaystyle\frac{(x-1)(x+2)^2}{-1-x}\le0\)
  5. \(\displaystyle\frac{x^2+4x+4}{2x^2-x-1}>0\)
  6. \(\displaystyle\frac{(2-x^2)(x-3)^3}{(x+1)(x^2-3x-4)}\ge0\)
  7. \(\displaystyle\frac{(x+2)(x^2-2x+1)}{4+3x-x^2}\ge0\)
  8. \(\displaystyle\frac{x^4-3x^3+2x^2}{x^2-x-30}\ge0\)
  9. \(\displaystyle\frac{x^2+2}{x^2-1}<-2\)
  10. \(\displaystyle\frac{2(x-4)}{(x-1)(x-7)}\ge\frac{1}{x-2}\)
  11. \(\displaystyle\frac{7}{(x-2)(x-3)}+\frac{9}{x-3}+1\le0\)
  12. \(\displaystyle\frac{(x-2)(x-4)(x-7)}{(x+2)(x+4)(x+7)}>1\)
  13. \(\displaystyle\frac{x^2-6x+9}{5-4x-x^2}\ge0\)
  14. \(\displaystyle\frac{x+1}{x-1}\ge\frac{x+5}{x+1}\)

Ответы

  1. \((-\infty;+\infty)\)
  2. (2;3)
  3. (-3;1)
  4. \((-\infty;-1)\cup[1;+\infty)\)
  5. \((-\infty;-2)\cup(-2;-1/2)\cup(1;+\infty)\)
  6. \([-\sqrt{2};-1)\cup(-1;\sqrt{2}]\cup[3;4)\)
  7. \((-\infty;-2)\cup(-1;4)\)
  8. \((-\infty;-5)\cup[1;2]\cup[6;+\infty)\cup\{0\}\)
  9. \((-1;0)\cup(0;1)\)
  10. \((1;2)\cup(7;+\infty)\)
  11. \([-5;1]\cup(2;3)\)
  12. \((-\infty;-7)\cup(-4;-2)\)
  13. \((-1;1]\cup(4;6]\)
  14. \((-5;-1)\cup\{3\}\)