Формулы для нахождения сумм

содержание справочника

1. \(1+2+3+...+n=\displaystyle\frac{n(n+1)}{2}\)
2. \(p+(p+1)+(p+2)+...+(p+n)=\displaystyle\frac{(n+1)(2p+n)}{n}\)
3. \(1^2+2^2+3^2+...+n^2=\displaystyle\frac{n(n+1)(2n+1)}{6}\)
4. \(1^3+2^3+3^3+...+n^3=\displaystyle\frac{n^2(n+1)^2}{4}\)
5. \(1^4+2^4+3^4+...+n^4=\displaystyle\frac{n(n+1)(2n+1)(3n^2+3n-1)}{30}\)
6. \(1+3+5+...+(2n-1)=n^2\)
7. \(1^2+3^2+5^2+...+(2n-1)^2=\displaystyle\frac{n(4n^2-1)}{3}\)
8. \(1^3+3^3+5^3+...+(2n-1)^3=n^2(2n^2-1)\)
9. \(1\cdot 2+2\cdot 3+...+n(n+1)=\displaystyle\frac{n(n+1)(n+2)}{3}\)
10. \(1\cdot 4+2\cdot 7+...+n(3n+1)=n(n+1)^2\)
11. \(1\cdot 2\cdot 3+2\cdot 3\cdot 4+...+n(n+1)(n+2)=\displaystyle\frac{1}{4}n(n+1)(n+2)(n+3)\)
12. \(1^2-2^2+3^2-4^2+...+(-1)^{n-1}n^2=(-1)^{n-1}\displaystyle\frac{n(n+1)}{2}\)
13. \(\displaystyle\frac{1}{1\cdot 2}+\frac{1}{2\cdot 3}+...+\frac{1}{n(n+1)}=\displaystyle\frac{n}{n+1}\)
14. \(\displaystyle\frac{1}{1\cdot 3}+\frac{1}{3\cdot 5}+...+\frac{1}{(2n-1)(2n+1)}=\displaystyle\frac{n}{2n+1}\)
15. \(\sin x+\sin 2x+\sin 3x+...+\sin nx=\displaystyle\frac{\sin\frac{n+1}{2}x\cdot\sin\frac{nx}{2}}{\sin\frac{x}{2}}\)
16. \(\cos x+\cos 2x+\cos 3x+...+\cos nx=\displaystyle\frac{\cos\frac{n+1}{2}x\cdot\sin\frac{nx}{2}}{\sin\frac{x}{2}}\)